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A circle has a center at (3,-2) and a radius of 5.Create the equation of the the circle:(x2+ (y)2 =IIWord Bank:2 10 +2 25 +3 5 -3Blank 1:Blank 2:Blank 3:

A circle has a center at (3,-2) and a radius of 5.Create the equation of the the circle-example-1

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Given a circle with a center at (3,-2) and a radius of 5. We can create the equation of the circle using the formula below;


(x-a)^2+(y-b)^2=r^2

x =x coordinate of circle point

a=x coordinate of the center point = 3

y=y coordinate of circle point

b=y coordinate of the center point =-2

r=radius of the circle = 5

We would then substitute the given values in the equation above;


\begin{gathered} (x-3)^2+(y-(-2))^2=5^2 \\ (x-3)^2+(y+2)^2=25 \end{gathered}

From the solution, we can proceed to fill in the blanks

ANSWER:

Blank 1: -3

Blank 2: +2

Blank 3: 25

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