x=-1, y =2 S { -1,2}
1) Solving that linear system
x + 2y = 3 x -5 To eliminate x
5× +5y = 5
-5x -10y = -15
5x +5y = 5
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-5y = -10
y =2
1.2 Plugging into the I equation:
x +2(2)= 3
x +4=3
x=-1
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