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Find the linear function that approximates f(x)= x^3+5x^2+4 at a =1

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The linear function that approximates the function is


y=f(1)+f^(\prime)(1)(x-1)

So we need to find f(1) and f'(1)


f(1)=(1)^3+5(1)^2+4=10

And,


\begin{gathered} f^(\prime)(x)=3x^2+10x \\ f^(\prime)(1)=3(1)^2+10(1)=13 \end{gathered}

Then, the linear function is


\begin{gathered} y=10+13(x-1) \\ y=10+13x-13 \\ y=13x-3 \end{gathered}

User Saket Mehta
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