Question

A 54.0-kg skier starts from rest from the top of a 67-m high slope. What is the speed of the skier on reaching the bottom of the slope?(Neglect friction in the question)

Answer 1

36.24 m/s

Explanation:

Given:

Mass (m) = 54 kg

Height (h) = 67 m

From the law of conservation of energy, we have that the initial energy is equal to the final energy

The initial energy is just gravitational potential energy since the skier is not moving at the bottom of the hill and the final energy is the potential energy that is converted into kinetic and thermal energy due to friction, if we ignore friction, we would be left with the following:

`\begin{gathered} E_P=E_C \\ \\ mgh=(1)/(2)mv^2 \\ \\ gh=(1)/(2)v^2 \\ \\ \text{ We replacing} \\ \\ (9.8)(67)=(1)/(2)v^2 \\ \\ v^2=2\cdot656.6 \\ \\ v=√(1313.2) \\ \\ v=36.24\text{ m/s} \end{gathered}`

The speed of the skier on reaching the bottom of the slope is 36.24 m/s