91.0k views
3 votes
What is the solution of x^2-1/x^2+5x+4<_0

2 Answers

9 votes

Answer: Answer: The Correct Answer Would be -4 < x ≤ 1 and x ≠ -1 (Option D)

Step-by-step explanation: I took the Test and It was 100% Correct, Just trust me! :)

User Tyler Clendenin
by
7.6k points
7 votes

Answer:

-4 < x < -1 ∪ -1 < x ≤ 1

Explanation:

The expression can be simplified, with a restriction.


(x^2-1)/(s^2+5x+4)\le0\\\\((x+1)(x-1))/((x+1)(x+4))\le 0\\\\(x-1)/(x+4) \le 0\qquad x\\e-1

This has a zero at x=1 and a vertical asymptote at x=-4. The function changes sign at both of these values of x. The rational function will be negative where the factors have different signs, between -4 and +1. The solution must exclude x = -1.

-4 < x < -1 ∪ -1 < x ≤ 1

What is the solution of x^2-1/x^2+5x+4<_0-example-1
User StiGMaT
by
6.9k points