Answer:
Explanations:
Given the operation below:
![(7.15*10^3)*(6.10*10^(-5))](https://img.qammunity.org/2023/formulas/chemistry/high-school/jq3yn1lbkl9rixl6x54bs7be84pt08a7um.png)
Grouping the operation into standard and exponential values will give:
![\begin{gathered} (7.15*6.10)*(10^3*`0^(-5)) \\ \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/high-school/sm9vsln68ujpg82a74gephonmg428yftpx.png)
Simplify the result
![\begin{gathered} (43.615)*(10^(3+(-5))) \\ (43.615)*10^(-2) \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/high-school/9527gspkfkoa9yfj8lydww28osv3msyg74.png)
Write the resulting product in standard form:
![\begin{gathered} =4.3615*10^1*10^(-2) \\ =4.3615*10^(1-2) \\ =4.3615*10^(-1) \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/high-school/tnqur5zppsn15ol769ayv65h3qkvqr80qs.png)
Hence the coefficient (green) is 4.3615 and the exponent (yellow) is -1.