Given:
The measurements are listed 6,9,2,5,4,10,3,12,2,7,7,8 .
Required:
To find mean median mode range variance and standard deviation.
Step-by-step explanation:
(1)
Mean =
![=(6+9+2+5+4+10+3+12+2+7+7+8)/(12)](https://img.qammunity.org/2023/formulas/mathematics/college/gldhubafbbg6ruj861m4462davrvp1lwzl.png)
![\begin{gathered} =(75)/(12) \\ \\ =6.25 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/flwn11an5ajn9vokrfr5qymdjerugsqw7d.png)
(2)
Median : Is the middle value when the data values have been sorted (or the average of the 2 middle values if there are an even number of data values).
![2,2,3,4,5,6,7,7,8,9,10,12](https://img.qammunity.org/2023/formulas/mathematics/college/3hpkzheqztowkap3e63ll4huzp9ipxffk2.png)
Now the middle terms are 6 and 7.
![\begin{gathered} =(6+7)/(2) \\ \\ =6.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/chdvbuwm8c2p21ug4v5z2nhm33vuuk83j2.png)
(3)
Mode: Is the data value(s) the occur with the greatest frequency.
Therefore, 2 and 7 are modes.
(4)
Range:
Range shows the mathematical distance between the lowest and highest values in the data set.
Therefore, from the given data 2 is the lowest value and 12 is the highest value,
![\begin{gathered} =12-2 \\ =10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/s36n0f0n044dhtebk7yxnn5u5jyqltgh5n.png)
Final Answer:
Mean : 6.25
Median : 6.5
Mode : 2 and 7
Range: 10