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What is an equation of the line that passes through the point (-1,6) and is parallelto the line 2x + y = 9?

User Kabucey
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1 Answer

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First, solve the given equation for y:

2x + y = 9

y = -2x + 9

the slope of the equation is m =-2.

Now, consider that all parallel lines have the same slope, then, the slope of the required line is m = -2.

Next, use the following general equation for a line:

y - yo = m(x - xo)

where (xo,yo) is any point on the line. Replace (xo,yo) = (-1,6) with m=-2 into the previous equation and solve for y:

y - 6 = -2(x - (-1))

y - 6 = -2x - 2

y = -2x - 2 + 6

y = -2x + 4

Hence, the equation of the line which crosses through the point (-1,6) and parallel to 2x + y = 9 is y = -2x + 4

User Wuct
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