Question

Do Example #2 please. Don’t forget to round to nearest hundreth.

Answer 1

Write out the general formula for finding the volume of a cone and a cylinder

`\begin{gathered} V_{\text{cone}}=(1)/(3)\pi r^2h \\ V_{\text{cylinder}}=\pi r^2h \end{gathered}`

Write out the given parameter in the question

`\begin{gathered} r_{\text{cone}}=1\text{ofeet} \\ h_{\text{cone}}=10\text{feet} \\ r_{\text{cylinder}}=10\text{feet} \\ h_{\text{cylinder}}=30\text{feet} \end{gathered}`

Substitute the given into the formula

`V_{\text{cone}}=(1)/(3)\pi r^2h=(1)/(3)*3.14*10^2*10=1046.67ft^3`
`V_{\text{cylinder}}=\pi r^2h=3.14*10^2*30=9420ft^3`

The volume of the silo is the addition of the volume of the cone and the volume of the cylinder

`V_{\text{silo}}=1046.67ft^3+9420ft^3=10466.67ft^3(\text{nearest hundredth)}`

Hence, the volume of the silo is 10466.67ft³