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The value of Kayla's investment can be modeled by the equation y = 2650(1.05) where z is the number of years invested and y is the value in dollars.Using the model, what will be the value of the investment after 25 years? Round your answer to the nearest dollar.A. $7,515OB. 58,974OC.59,164OD. 58,828

The value of Kayla's investment can be modeled by the equation y = 2650(1.05) where-example-1
User AaronR
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Solution:

Given the equation:


\begin{gathered} y=2650(1.05)^x \\ where \\ x\text{ is the number of years invested } \\ y\text{ is the value in dollars} \end{gathered}

To determine the value of the investment after 25 years, we have


\begin{gathered} y=2650(1.05)^(25) \\ =2650*(1.05)^(25) \\ =8973.84059 \\ \\ \Rightarrow y\approx\$8974\text{ \lparen nearest dollar\rparen} \end{gathered}

Hence, to the nearest dollar, we have the value of the investment to be


\$\text{8974}

The correct option is

User Duane
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