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What values if x are solutions of the equation. square root 1 - X squared plus 2 equals 3

User Bdrelling
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We have to find the values of x that are solution for the equation


√(1-x^2)+2=3

To solve this equation, the first thing we will do is pass, the 2 that is on the left side, to the right side with the opposite sign


\begin{gathered} √(1-x^2)=3-2 \\ \\ √(1-x^2)=1 \end{gathered}

Now we will take power two, on both sides of the equation


\begin{gathered} (√(1-x^2))^2=1^2 \\ \\ 1-x^2=1 \end{gathered}

Now we will pass the x square to the rigth with opposite sign, and the 1 on the right to the left with opposite sign


\begin{gathered} 1-1=x^2 \\ \\ 0=x^2 \end{gathered}

Finally, we take square root on both sides to find


\begin{gathered} \pm√(0)=√(x^2) \\ \\ \pm0=x \end{gathered}

Where we have to include both square roots, the positive and the negative one. In this specific case, both are the same, because the solution is 0. Therefore, we conclude:


x=0

We conclude that the provided equation has a unique solution, and that this solution is 0.

User Photon Light
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