Given function :
F(x) = 6x+4 and g(x)=22x-5
to find the value of f(-3) +g(10)
firts we calculate the value of f(-3) by substitute the x= -3 ine the function f(x)
F(x) =6x+4
f(-3) = 6(-3) +4
f(-3)= -18+4
f(-3) = -14
Now, similarly for the value of g(10) substitute x=10 in the function g(x)
g(x) = 22x-5
g(10) = 22 (10) -5
g(10) = 220-5
g(10) = 215
Since we need to calculate the value of f(-3) + g(10)
substitute the value of f(-3) and g(10)
f(-3) + g(10) = -14 +215
f(-3) + g(10) = 201
Answer : the value of f(-3) + g(10) is 201.