62.9k views
4 votes
Calculus early transcendental functions. Find the derivative of the function. Leave the answer as appositive integer.

Calculus early transcendental functions. Find the derivative of the function. Leave-example-1

1 Answer

4 votes

SOLUTION

The given equation is


y=(2)/(x^4)-x^3+2
\begin{gathered} \text{ given a function } \\ y=x^n \\ (dy)/(dx)=nx^(n+1) \end{gathered}

Then for the given function


y=(2)/(x^4)-x^3+2

The derivative of the function above becomes


\begin{gathered} y=2x^(-4)-x^3+2 \\ Apply\text{ the sum and difference rule of derivative } \\ (dy)/(dx)=(-4*2)x^(-4-1)-3x^(3-1) \end{gathered}

Then we have


\begin{gathered} (dy)/(dx)=-8x^(-5)-3x^2 \\ \\ (dy)/(dx)=-(8)/(x^5)-3x^2 \end{gathered}

Therefore the derivative of the function above is

dy

User Anroots
by
5.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.