Question

Find the equation of a circle with the same center as the circle in the graph above and that passes through a point 2 units away from the given circle. A.x²(y-2)² = 9 B.x²+(y-2)² = 1 C. (x-2)²+ y² = 3 D. (x-2)² + y² = 9

Answer 1

step 1

Find out the center of the circle in the graph

the center is the point (0,2)

step 2

The radius of the second circle is equal to

r=1+2=3 units

therefore

the equation of the circle is

x^2+(y-2)^2=3^2

x^2+(y-2)^2=9

the answer is option A