Given:
A linear equation 2y = 4x - 8.
To find:
Graph from given linear equation.
Step-by-step explanation:
Intercept form of straight line
![(x)/(a)+(y)/(b)=1](https://img.qammunity.org/2023/formulas/mathematics/college/xb9g6tutgm0yln4sqsbqmmf3umsljoemrm.png)
Where a ,b are intercepts on x and y-axis.
Solution:
We have linear equation 2y = 4x - 8.
Now,
![\begin{gathered} 4x-2y=8 \\ (x)/(2)+(y)/(-4)=1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e9u9122enwl78whzaf9l5h48ozftq8d900.png)
Here, 2 and -4 are x and y intercept respectively.
So, graph will look like,
Hence, this is the graph for given linear equation.