The period of a pendulum is given by:
![T=2\pi\sqrt[]{(L)/(g)}](https://img.qammunity.org/2023/formulas/physics/college/h8quhyohkhg6oj9xkblumno6z1ebdjigmr.png)
where L is the lenght of the pendulum and g is the acceleration of gravity.
We know that the repaired pendulum has a length of 114.63 cm, then its period is given by:
![\begin{gathered} T=2\pi\sqrt[]{(1.1463)/(9.8)} \\ T=2.149 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/9gj8pvgl1ty17bktycc9khcg9jn8ncmfk0.png)
Therefore the repaired pendulum has a period of 2.149 seconds.
We know that a day has 86400 seconds, to determine how many swings the pendulum make in a day we divide the total amount of seconds in a day by the period of the clock, then we have:

Therefore the clocks swings 40200 times a day (rounded to three significant figrues)