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select the curve represented by the parametric equation indicate the orientation of the curve.x=4-5ty=5+4t

User Cleong
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1 Answer

1 vote

Multiply both sides of the first equation by 4.


4x=16-20t

Multiply both sides of the second equation by 5.


5y=25+20t

Add the obtained equations.


4x+5y=41

Identify the y-intercept of the linear equation. Substitute 0 to the value of x and then solve for y.


\begin{gathered} 4(0)+5y=41 \\ 5y=41 \\ y=(41)/(5) \\ y=8.2 \end{gathered}

Thus, the y-intercept is (0,8.2).

Therefore, the graph whose y-intercept is (0,8.2) and whose x-intercept is (10.25,0) is the graph that represents the parametric equations.

select the curve represented by the parametric equation indicate the orientation of-example-1
User Gerald Ferreira
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