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3 votes
A(a^2 - x) = b(b^2 -x) ​

2 Answers

3 votes


{ \purple{ \sf{a( {a}^(2) - x) = b( {b}^(2) - x)}}}

Multiply a with the terms in bracket and b with the terms in the bracket you will get


{ \red{ \boxed{ \bold{ {a}^(3) - ax = {b}^(3) - bx}}}}

User Ben McRae
by
3.3k points
1 vote

Explanation:

a(a²-x)=b(b²-x)

=a³-ax=b³-bx

User Vijayashankard
by
3.0k points