We have E(7,-2) and E'(2,0).
We can think of E' as the image of E after a translation (a,b), where we have to find the values of a and b.
We can write:

Then, we can find a and b as:

The translation is then (-5,2).
Then, we can write the rule as:

Answer: (x,y) --> (x-5,y+2)