Given:
The length of the floor is 7 feet greater than its width w.
Therefore, length, l=7+w.
Since the dimensions are increased by 2 feet,
The new width, w'=w+2.
The new length, l'=l+2=7+w+2=9+w.
Now, the new area N of the floor of the rectangular cage is,

Therefore, the new area of the floor of the rectangular cage is,
