Question

Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them. How far apart are these charges?

Answer 1

25 cm

Step-by-step explanation:

F = k q₁q₂/r²

Substituting values : let the distance be x.

3.6 = (9 x 10^9) (5 x 10^(-6) (5 x 10^(-6)) / x²

3.6 = (225 x 10^(9-6-6) )/x²

3.6 = (225 x 10^(-3) / x²

x² = 225/3.6 x 10^(-3)

x² = 62.5x10x10^(-4) [10^(-3)=10x10^(-4)]

x = √(625 x 10^(-4) )

x = 25 x 10^(-2)

Or, x = 25 cm