Question

The weekly revenue for a company is r=-4p^2+40p+887, where p is the price of the company’s product. Use the discriminant to find whether there is a price for which the weekly revenue would be $1200

Answer 1

No, there is no price for which the weekly revenue would be 1200

Explanation:

If r = 1200

`-4p^2+40p+887=1200\\\\\implies -4p^2+40p-313=0`

Therefore,
`a=-4, \ \ \ b=40, \ \ \ c=-313`

discriminant =
`b^2-4ac`

`\implies 40^2-4(-4)(-313) = 1600 - 5008=-3408\\\\-3408<0 \implies \textsf{no real solutions}`