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You roll a number cube numbered from 1 to 6 p(1 or 4)

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Hllo!

We have a cube with 6 different sides: 1, 2, 3, 4, 5, 6.

The exercise asks the probability of otaining 1 or 4.

First, let's think about the probability of obtaining the number 1.

Well, there's 1 option in 6 possible. So, we can write it as 1/6.

To obtain the number 4, we'll follow the same line of reasoning.

Now, remembr: we have the word "OR". It means tahat we have to sum up the obtained results.

Knowing it, let's calculate:


\begin{gathered} 1\text{ or 4} \\ (1)/(6)+(1)/(6)=(1+1)/(6)=(2)/(6) \end{gathered}

Now, let's simplify it by dividing the numerator and denominator by 2:


(2/2)/(6/2)=(1)/(3)

Answer:

1/3.