1 Answer

Kevin Velasco · Answer 1 · 2023-04-22T21:26:38+0000

Given:

$f(x)=\begin{cases}{x^2}\text{ .............If }x<0 \\ {-1\text{ ............If }x=0} \\ {3x+4....\text{ If }x>0}\end{cases}$

Find-:

$\begin{gathered} (a)f(-2) \\ \\ (b)f(0) \\ \\ (c)f(1) \end{gathered}$

Sol:

(a)

At f(-2) the value of x is less then zero (0) then function apply is:

$\begin{gathered} f(x)=x^2 \\ \text{ at }x<0 \end{gathered}$

So the value is:

$\begin{gathered} f(x)=x^2 \\ \\ f(-2)=(-2)^2 \\ \\ f(-2)=4 \end{gathered}$

(b)

At f(0) the value of x is zero (0) then function value at x = 0 is:

$\begin{gathered} f(x)=-1 \\ \text{ at }x=0 \end{gathered}$

So, the value is:

$\begin{gathered} f(x)=-1 \\ f(0)=-1 \end{gathered}$

(c)

At f(1) then the value of x is 1 so the function apply is:

$\begin{gathered} f(x)=3x+4 \\ \\ \text{ At }x>0 \end{gathered}$

So, the value is:

$\begin{gathered} f(x)=3x+4 \\ \\ f(1)=3(1)+4 \\ \\ f(1)=3+4 \\ \\ f(1)=7 \end{gathered}$

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