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Consider the image that shows a tower anchored by a guy with the guy wire is attached at point b on the tower 119 feet above the ground and then anchored to the ground at point a 120 feet from the base of the tower.

Options are: A) sin0= 119/120, B) sin0= 120/119, C) sin0= 119/169, and D) sin0= 120/169

Consider the image that shows a tower anchored by a guy with the guy wire is attached-example-1
User Veeman
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2 Answers

11 votes
11 votes

Answer:

Explanation:


sin\theta=(opposite)/(hypotenuse)\\ \\ sin\theta=(119)/(169)\ (answer\ C)

User Sumid
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13 votes
13 votes

The ratio
\sin \theta=(119)/(169) is accurate for the described tower and guy-wire configuration.

Let's denote the angle between the tower and the guy wire as θ. The length of the guy wire is the hypotenuse of a right triangle formed by the tower, the ground, and the guy wire.

According to trigonometry, the sine of an angle in a right triangle is defined as the ratio of the opposite side to the hypotenuse. In this case, the opposite side is the height of the tower at point B (119 feet), and the hypotenuse is the length of the guy wire.

Therefore, the sine of angle θ (sin θ) is given by:


\sin \theta=\frac{\text { Opposite }}{\text { Hypotenuse }}=\frac{119}{\text { length of guy wire }}

Now, we need to find the length of the guy wire. This can be determined using the Pythagorean Theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b):


c^2=a^2+b^2

In this case, a is the height of the tower at point B (119 feet), b is the distance from point A to the base of the tower (120 feet), and c is the length of the guy wire.


\begin{aligned}& c^2=119^2+120^2 \\& c^2=14161+14400 \\& c^2=28561 \\& c=√(28561) \\& c=169\end{aligned}

Now that we have the length of the guy wire (169 feet), we can substitute it back into the original expression for sin θ:


\sin \theta=(119)/(169)

Therefore, the correct answer is: C)
\sin \theta=(119)/(169)

User Jeff Irwin
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