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Question 2Use 3.14 for pi and round to the nearest tenth

Question 2Use 3.14 for pi and round to the nearest tenth-example-1

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Answer:

254.3 cubic mi.

Step-by-step explanation:

The given composite figure is made up of a cylinder and a hemisphere with the following dimensions:

Cylinder

• Height = 7 mi

,

• Base Radius = 3 mi

Hemisphere

• Base Radius = 3 mi

Thus:


\begin{gathered} \text{Volume of the composite figure=Vol. of Cylinder+Vol. of Hemisphere} \\ =\pi r^2h+(2)/(3)\pi r^3 \end{gathered}

Substitute the given values:


\begin{gathered} V=(\pi*3^2*7)+((2)/(3)*\pi*3^3) \\ =63\pi+18\pi \\ =81\pi\; =81*3.14 \\ \approx254.3\text{ }mi.^3\text{ (to the nearest tenth)} \end{gathered}

The volume of the composite figure is 254.3 cubic mi.

User Pratteek Shaurya
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