Question

A series RLC circuit has a resistance of 7.17 ohms, a capacitance of 2.59 mF, and an inductance of213.91 mH. The circuit is connected to a 60 Hz frequency source with a fixed rms output of 63.51 V.• What is the phase angle?

Answer 1

Given:

Resistance, R = 7.17 Ohms

Capacitance, C = 2.59 mF

Inductance, L = 213.91 mH

Frequency, f = 60 Hz

To find:

The phase angle.

Step-by-step explanation:

The inductive reactance can be calculated as:

`X_L=2\pi fL=2\pi*60*213.91*10^(-3)=80.6422\text{ Ohm}`

The capacitive reactance can be calculated as:

`X_C=(1)/(2\pi fC)=(1)/(2\pi*60*2.59*10^(-6))=(1)/(9.7640*10^(-4))=1024.1404\text{ Ohm}`

The phase angle is given as:

`\varphi=tan^(-1)((X_L-X_c)/(R))=tan^(-1)((80.6422-1024.1404)/(7.17))=-89.56\degree`

Final answer:

The phase angle is -89.56 °.