We know that:
- a rocket is launched from the top of an 8-foot ladder.
- It’s initial velocity is 128 feet per second, and it is launched at an angle of 60* with respect to the ground
And we must write parametric equations that describe the motion of the rocket as a function of time
To write the parametric equations we need to know that the parametric general equations for a Projectile Motion are:
![\begin{gathered} x=\left(v_0cos\theta\right)t \\ y=h+\left(v_0sin\theta\right)t-16t^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/m1rthi1qpwz320eht9vlsaqq89235ym1s6.png)
Where,
v0 represents the initial velocity
h represents the initial height
θ represents the angle respect to the ground
In our case,
![\begin{gathered} v_0=128(feet)/(sec) \\ h=8feet \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/145z66j2e4ndjydej5m613pkya8vi6fw5c.png)
Finally, replacing in the parametric equations:
![\begin{gathered} x=\left(128cos60\degree\right)t \\ y=8+\left(128sin60\degree\right)t-16t^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/76rejxyner4gc3t01nkg3dyn0o2jcywiug.png)
ANSWER:
![\begin{gathered} x=(128cos60\operatorname{\degree})t \\ y=8+(128s\imaginaryI n60\degree)t-16t^2 \end{gathered}]()