Question

What is the equation of the line that passes through the point (-2, 1) and has aslope of 3/2?

Answer 1

We will find the equation that passes through the point (-2, 1) & m = 3/2, using the following expression:

`y-y_1=m(x-x_1)`

Here, the point is (x1, y1) and the slope m, we will replace and solve for y:

`y-1=(3)/(2)(x-(-2))\Rightarrow y-1=(3)/(2)x+3`
`\Rightarrow y=(3)/(2)x+4`

So, the equation is y = 3/2x + 4.