Question

Three squares arejoined at the verticesto form a right triangle.The figure on the rightshows the lengths of aside of two of the threesquares. What could bethe length of a side ofthe third square?A-34 inchesB-26 inchesC-32 inchesD-28 inches

Answer 1

Given:

Length of a side for square 1 = 10 in

Length of a side for square 2 = 24 in

A square has 4 equal sides.

Since the three squares form a right triangle, to find the length of the third square, use pythogoras theorem.

We have the formula:

`\begin{gathered} c^2=a^2+b^2 \\ \\ c=\sqrt[]{a^2+b^2} \end{gathered}`

where, a = 10 in

b = 24 in

We have:

`\begin{gathered} c=\sqrt[]{10^2+24^2} \\ \\ c=\sqrt[]{100+576} \\ \\ c=\sqrt[]{676} \\ \\ c=26\text{ } \end{gathered}`

Therefore, the length of a side of the third square is 26 inches.

ANSWER:

B. 26 inches