Question

A plastic bubble of thickness 102 nmhas its strongest (m = 1) reflectionmaximum at 604 nm. What is the indexof refraction n for the bubble?(Hint: If you leave the wavelength in nm,the answer will be in nm. No conversionnecessary.)(No unit.)

Answer 1

Given:

m = 1

d = 102 nm

λ = 604 nm

n = ?

Apply:

`d=(1)/(2)((m-(1)/(2))\lambda)/(n)`
`n=((m-1/2)\lambda)/(2d)`
`n=\frac{(1-1/2)604}{2\text{ \lparen102\rparen}}`

n= 1.48 nm