This kind of exercise refers to the probability of exatly "x" successes on "n" repeated trials in an experiment which has a possible outcome.
If the probability of succes on an individial trial is p, then the probability is represented by:
![P=\text{nCx}\cdot p^x\cdot(1-p)^(n-x)](https://img.qammunity.org/2023/formulas/mathematics/college/ot6nie521n9l8ag37rq45iawaal63wriwp.png)
Here nCx indicates the number of different combinations of x objects selected from a set of n objects.
Using the given data, we have:
![\begin{gathered} P=18\text{C11}\cdot(0.8^(11))\cdot(1-0.8)^(18-11) \\ P=31824\cdot(8.589\cdot10^(-2))\cdot(1.28\cdot10^(-5))^{} \\ P=0.035 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ohgsy02h6uj12qsdvbabroo62uvot3wd1w.png)