Question

What is the coefficient of kinetic friction between the bag and the ground

Answer 1

`\begin{gathered} \sum_{n\mathop{=}0}^(\infty)Fx=ma \\ m=6.7kg \\ \\ v^2=2ad \\ (1.1m/s)^2=2a(5.05m) \\ a=0.12m/s^2 \end{gathered}`
`\begin{gathered} \sum_{n\mathop{=}0}^(\infty)Fx=0.12m/s^2\cdot6.7kg=0.803N \\ \sum_{n\mathop{=}0}^(\infty)Fx=28N-Ff=0.803N \\ 28N-0.803N=27.2N=mg\kappa \\ 27.2N=(6.7kg)(9.81m/s^2)\kappa \\ 0.41=\kappa \end{gathered}`