Question

The permeter of a rectangle wooden deck is 90ft the decks length is 5 ft less than 4 times its width what are the dimensions of the wooden deck

Answer 1

Given:

Perimeter of rectangular wooden deck = 90 ft

Length is 5 feet less than 4 times its width.

Let's find the dimensions of the wooden deck.

Since the length is 5 feet less than 4 times its width, we have:

L = 4W - 5

Where:

L represents the length

W represents the width.

Now, apply the formula for the perimeter of a rectangle:

P = 2W + 2L

Where P is the perimeter.

Plug in 90 for P and (4W - 5) for L:

90 = 2W + 2(4W - 5)

Now, apply distributive property:

90 = 2W + 2(4W) + 2(-5)

90 = 2W + 8W - 10

90 = 10W - 10

10W = 90 + 10

10W = 100

Divide both sides by 10:

`\begin{gathered} (10W)/(10)=(100)/(10) \\ \\ W=10 \end{gathered}`

Substitute 10 for W in the first equation:

`\begin{gathered} L=4(10)-5 \\ L=40-5 \\ L=35 \\ \end{gathered}`

We have the solutions:

W = 10

L = 35

Therefore, the dimensions of the wooden deck are:

• Length of the wooden deck, L = 35 ft

,

• Width of the wooden deck, W = 10 ft

ANSWER:

• Length of wooden deck = 35 ft

,

• Width of wooden deck = 10 ft