
therefore, the maximum number of foils Justin can have is 5
Step-by-step explanation
Step 1
set the ineequality
Let x represents the number of foils
and
fee : $ 37.50
rate per foil = $ 6 per foil
total : no more than 70 ( so 70 or smaller)
so
total = fee+ ( cost of foils)
the cost of foils can be calculated using
cot of foils= rate*number of foils
replace
cost of foils= 6x
so, the total cost is
total = fee+ ( cost of foils)
total = 37.5+ 6x

but, remember the total must be equal or smaller than 70
henc e

Step 2
now, let's solve the inequality

as the unit is per foil, we need to use whole numbers, so the answer is

therefore, the maximum number of foils Justin can have is 5
I hope this helps you