60.0k views
3 votes
Find the perimeter of the triangle whose vertices are (1,-4),(-5,0),and (-2,-9). Write exact answer do not round

Find the perimeter of the triangle whose vertices are (1,-4),(-5,0),and (-2,-9). Write-example-1
User J Manuel
by
7.7k points

1 Answer

3 votes

We would calculate the distance between the vertices by applying the formula for calculating the distance between two points which is expressed as

distance = √(x2 - x1)^2 + (y2 - y1)^2

Considering (1,-4) and (-5,0),

x1 = 1, y1 = - 4

x2 = - 5, y2 = 0

Distance = √(- 5 - 1)^2 + (0 - - 4)^2 = √(- 6)^2 + (4)^2 = √52 = 2√13

Considering (-5,0),and (-2,-9),

x1 = - 5, y1 = 0

x2 = - 2, y2 = - 9

Distance = √(- 2 - - 5)^2 + (- 9 - 0)^2 = √(- 2 + 5)^2 + (- 9)^2 = √90 = 3√10

Considering (1,-4) and (-2,-9),

x1 = 1, y1 = - 4

x2 = - 2, y2 = - 9

Distance = √(- 2 - 1)^2 + (- 9 - - 4) = √(- 3)^2 + (- 5)^2 = √34

Perimeter = sum of the length of each side

Perimeter = 2√13 + 3√10 + √34

User Icky
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories