Question

Find the first four terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.an = 6n − 8

Answer 1

Given

`a_n=6n-8`

To find: The first four terms of the sequence.

Step-by-step explanation:

It is given that,

`a_n=6n-8`

Then,

For n=1,

`\begin{gathered} a_1=6(1)-8 \\ =6-8 \\ =-2 \end{gathered}`

For n=2,

`\begin{gathered} a_2=6(2)-8 \\ =12-8 \\ =4 \end{gathered}`

For n=3,

`\begin{gathered} a_3=6(3)-8 \\ =18-8 \\ =10 \end{gathered}`

For n=4,

`\begin{gathered} a_4=6(4)-8 \\ =24-8 \\ =16 \end{gathered}`

Hence, the first four terms of the sequence is -2, 4, 10, 16.