We have the following current and resistance:
![\begin{gathered} i=4+j2 \\ R=2-j3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nm6ioadaru07i539019uv7zzl5gl6hmwum.png)
Where 'j' represents the imaginary number. The voltage of a circuit is given by the product of the current and resistance. To find the voltage of this circuit we just need to multiply those two values:
![V=i\mathrm{}.R=(4+j2)\mathrm{}(2-j3)=8-8j-6j^2=8-8j+6=14-8j](https://img.qammunity.org/2023/formulas/mathematics/college/vutimgdmyq6ra0t8pm44sloh373zwdke3f.png)
Then, this is our answer. The voltage is:
![14-8j](https://img.qammunity.org/2023/formulas/mathematics/college/1g66ug2gdxwoy3505uhkczpvx7eiqcrsgl.png)