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What is the area of the regular pentagon with a radius of 18mm?

What is the area of the regular pentagon with a radius of 18mm?-example-1
User Ede
by
7.7k points

1 Answer

5 votes

Given:

Required:

We need to find the area of given pantagon

Step-by-step explanation:

First take one triangle with center angle is


(360)/(5)=72\degree

now triangle is as

use sin function to find b


\begin{gathered} sin36=(b)/(r) \\ \\ b=10.58\text{ mm} \end{gathered}

B is


B=2b=2*10.58=21.16\text{ mm}

now to find h

use cos function


\begin{gathered} cos36=(h)/(r) \\ \\ h=14.56\text{ mm} \end{gathered}

area of one triangle is


a=(1)/(2)Bh=(1)/(2)*14.56*21.16=154.07\text{ mm}^2

area A of pentagone is

Final answer:


A=5a=770.35\approx770\text{ mm}^2

What is the area of the regular pentagon with a radius of 18mm?-example-1
What is the area of the regular pentagon with a radius of 18mm?-example-2
User Rich Scriven
by
8.2k points

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