Given,
The force exerted, F=30 N
The distance for which the force is applied, s=6.0 m
The mass of the object, m=10 kg
The initial velocity, u=0 m/s
From Newton's second law,

Thus the acceleration of the body is given by,

From the equation of the motion,
![\begin{gathered} v^2=u^2+2as \\ \Rightarrow v^2=u^2+2*(F)/(m)* s \\ \Rightarrow v=\sqrt[]{u^2+2*(F)/(m)* s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/fv4yrfawceovdylp73obfhh94mgp6ta4r0.png)
On substituting the known values, the final velocity of the object is
![\begin{gathered} v=\sqrt[]{0+2*(30)/(10)*6} \\ =6\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/mnc8mzvmtmb2ar1l0td8bo0pwfv8845q41.png)
Thus the velocity of the object is 6 m/s