Question

A rock with a mass of 1.0 kg is at the top of a hill and has a potential energy of 50j.If the rock rolls to the bottom of the hill, what is its kinetic energy at the bottom of the hill?

Answer 1

Given:

The mass of the rock is

`m=1.0\text{ kg}`

The potential at the top of the hill is

`PE=50\text{ J}`

To find:

If the rock rolls to the bottom of the hill, what is its kinetic energy at the bottom of the hill?

Step-by-step explanation:

According to energy conservation, the kinetic energy at the bottom equals the potential energy at the top.

So, the kinetic energy at the bottom is

`\begin{gathered} (KE)_(bottom)=(PE)_(top) \\ =50\text{ J} \end{gathered}`

Hence, the kinetic energy at the bottom of the hill is 50 J.