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Consider the square root function f(x) = sqrt x + 2 + 1 to complete the table of values below. find each missing value and then graph and connect the points for f(x). x -3, -2, -1 ,2, 7f(x) _ _ _ _ _

User Thadk
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Given the function :


f(x)=\sqrt[]{x+2}+1

We need to find each missing value

Given x = -3 , -2 , -1 , 2 , 7

So, substitute with each value of x to find the corresponding value of f(x)


x=-3\rightarrow f(x)=\sqrt[]{-3+2}+1=\sqrt[]{-1}+1

So, there is no value for f(x) at x = -3 (the function undefined because the square root of -1)


\begin{gathered} x=-2\rightarrow f(x)=\sqrt[]{-2+2}+1=\sqrt[]{0}+1=0+1=1 \\ \\ x=-1\rightarrow f(x)=\sqrt[]{-1+2}+1=\sqrt[]{1}+1=1+1=2 \\ \\ x=2\rightarrow f(x)=\sqrt[]{2+2}+1=\sqrt[]{4}+1=2+1=3 \\ \\ x=7\rightarrow f(x)=\sqrt[]{7+2}+1=\sqrt[]{9}+1=3+1=4 \end{gathered}

the graph of the function and the points will be as shown in the following image :

Consider the square root function f(x) = sqrt x + 2 + 1 to complete the table of values-example-1
User ClaytonJY
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