Question

What is the equation of the line that passes through the point (-6, -8) and has aslope of 1/3?

Answer 1

x-3y=18

Step-by-step explanation:

To determine the equation of the line, we use the point-slope form

`y-y_1=m(x-x_1)`

Given that:

`m=(1)/(3),(x_(1,)y_1)=(-6,-8)`

We therefore have:

`y-(-8)=(1)/(3)(x-(-6))`

We can then simplify:

`\begin{gathered} y+8=(1)/(3)(x+6) \\ 3(y+8)=x+6 \\ 3y+24=x+6 \\ 3y-x=6-24 \\ 3y-x=-18 \\ x-3y=18 \end{gathered}`