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Find F(X)= (X^2-1)^3/(1+2X)^5

User Oeter
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1.) Evaluating that function, to find the points of interception of the graph i.e. when y=0. So


\begin{gathered} f(x)=((x^2-1)^3)/((1+2x)^5)\Rightarrow0=((x^2-1)^3)/((1+2x)^5) \\ (x^2-1)^3=0 \\ \sqrt[3]{(x^2-1)^3}=0 \\ x^2-1=0 \\ x^2=1 \\ x=1,-1 \end{gathered}

As we can see, when we set y=0, and cross multiply, we can set the points that intercept the x-axis (-1,0) and (1,0)

User Chaska
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