Question

How much of a 0.250M sucrose solution must be used to prepare 400.0mL of a 0.0310M solution?

Answer 1

1) Preparing a dilution

`C1\cdot V1=C2\cdot V2_{}`

C1: Initial concentration.

V1: Initial volume.

C2: final concentration.

V2: final volume.

2) List known values

C1: 0.250 M sucrose

V1:

C2: 0.0310 M sucrose

V2: 400.0 mL

3) Plug in known values and solve for V2

`0.250\text{ M}\cdot V1=0.0310M\cdot400.0mL`
`V1=(0.0310M\cdot400.0mL)/(0.250M)=49.6mL`

The solution should be made as follows

Add 49.6mL of 0.250M sucrose to 350.4mL of water to get 400.0mL of 0.0310 M sucrose.