Question

What is the equation of the line that goes through the points (- 2, 1) and (0, 4) ? (Write your answer in standard form .)

Answer 1

`3x-2y+8=0`

Explanation:

The slope of the line that goes through the points (-2, 1) and (0, 4) is

`(4-1)/(0-(-2)) = (3)/(2)`

The slope of the line that goes through the points (x, y) and (0, 4) is

`(4-y)/(0-x) = (4-y)/(-x)`

So
`(3)/(2)=(4-y)/(-x)\\-3x=2(4-y)=8-2y\\3x-2y+8=0`