Question

The sum of three consecutive interferes is 93. What are the integers?

Answer 1

You have to find three integers that add up to 93

Syimbolize the first integer using the variable x

Then the next consecutive integer will be x+1

And the third consecutive integer will be x+2

You can express the equivalency as:

x+(x+1)+(x+2)=93

x+x+1+x+2=93

3x+3=93

3x=90

x=30

The first ingteger is 30, the second is 31 and the third is 32

The second integer is x+1= 30+1= 31

The third integer is x+2= 30+2=32