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A sphere and a cylinder each have the same radius. The cylinder has a height that is triple the radius. How do I create a simplified expression to show how many times greater the larger figure is than the other figure?

User Teebot
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1 Answer

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we are given a sphere and a cylinder with the following conditions:


r_s=r_c=r
h=3r

The volume of the sphere is given by the following formula:


V_s=(4)/(3)\pi r^3

The volume of the cylinder is given by:


V_c=\pi r^2h

Since the height "h" is three times the radius "r", we get_


V_c=3\pi r^3

Now we divide both sides by 3:


(V_c)/(3)=\pi r^3

Now we replace the right sides of the volume of the sphere for its equivalent in the volume of the cylinder:


V_s=(4)/(3)((V_c)/(3))

Solving:


V_s=(4)/(9)V_c

Multiplying by 9/4:


(9)/(4)V_s=V_c

Therefore, the cylinder occupies 9/4 of the volume of the sphere.

User Mark Robbins
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