if we draw the terminal point and draw a line to it from the origin we obtain something like this
This can form a right triangle in which we must find the hypotenuse
![\begin{gathered} a^2+b^2=c^2 \\ ((1)/(2))^2+(\frac{\sqrt[]{3}}{2})^2=c^2 \\ (1)/(4)+(3)/(4)=c^2 \\ (4)/(4)=c^2 \\ c=\sqrt[]{1} \\ c=1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/irldgc63int0brxkts0fuwjnoel9iqkl9g.png)
the sin is defines as the opposite (y) divided by the hypotenuse, in this case since the hypotenuse is equal to 1, the sin is equal to:
