Question

The length of a rectangular dog run is 5 feet more than three times the width, w, and the perimeter of the dog run is 30 feet. Solve the equation 2w+2(3w+5)=30 to find the width, w, of the dog run. Then find the length, 3w+5,of the dog run.

Answer 1

`\begin{gathered} 2w+2(3w+5)=30 \\ 2w+6w+10=30 \\ 2w+6w=30-10 \\ 8w=20 \\ w=(20)/(8) \\ w=2.5 \\ \text{The width is 2.5ft} \\ \text{length = 3w+5} \\ \text{length}=3\cdot(2.5)+5 \\ \text{length}=12.5ft \\ \text{The length is 12.5ft} \end{gathered}`